How to find the Volume of a Square Pyramid?

How to find the book of a Square Pyramid ? A square pyramid is a cubic geometric imprint with a square base and four triangular sides connected at the vertex. It has five sides and is called a polyhedron or more specifically a pentahedron. The triangular sides of the pyramid are called its faces whereas the target that lies above its base is called the vertex. It has 8 edges, 5 vertices, and 4 faces in sum. It becomes a right squarely pyramid if the vertex lies sheer above the square ’ s center. An equilateral straight pyramid is formed if all edge lengths are equal .

Volume of Square pyramid formula

A square pyramid ’ s book is defined as the space enclosed within its five faces. To calculate the bulk, values of base area and stature of hearty pyramid are needed. Its rule equals product of base area and stature divided by 3. The standard unit of measurement is cubic meters ( m3 ).

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V = 1/3 × A × h where, V is the volume, A is the base area, planck’s constant is the stature of the square pyramid .

In terms of root distance and altitude of the square pyramid, the formula for volume is given by ,

V = 1/3 × a2 × h where, V is the bulk, a is the base duration, heat content is the altitude of the square pyramid .

Let ’ s take an example to understand how we can calculate the volume of a square pyramid. Example: Calculate the volume of a feather pyramid of base area 90 sq. thousand and height 5 thousand. Step 1: Note the base area and height of the square pyramid. In this example, the base sphere of the pyramid is 90 sq. megabyte and altitude is 5 megabyte. Step 2: We know that the volume of a square pyramid is equal to 1/3 × A × h. Substitute the given measure of basis area and height in the formula. Step 3: so, the book of trilateral prism is calculated as, V = 1/3 × 90 × 5 = 150 copper. thousand .

Sample Problems

Problem 1. Calculate the volume of a square pyramid of base area 60 sq. m and height 10 m. Solution:

We have, A = 60 hydrogen = 10 Using the rule we get, V = 1/3 × A × hydrogen = 1/3 × 60 × 10 = 200 copper. megabyte

Problem 2. Calculate the volume of a square pyramid of base area 150 sq. m and height 20 m. Solution:

We have, A = 150 planck’s constant = 20 Using the rule we get, V = 1/3 × A × henry = 1/3 × 150 × 20 = 1000 copper. m

Problem 3. Calculate the base area of a square pyramid if its volume is 300 cu. m and height is 10 m. Solution:

We have, V = 300 hydrogen = 10 Using the convention we get, V = 1/3 × A × hydrogen = > A = 3V/h

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= > A = 3 ( 300 ) /10 = > A = 90 sq. molarity

Problem 4. Calculate the base area of a square pyramid if its volume is 120 cu. m and height is 5 m. Solution:

We have, V = 120 heat content = 5 Using the formula we get, V = 1/3 × A × h = > A = 3V/h = > A = 3 ( 120 ) /5 = > A = 72 sq. megabyte

Problem 5. Calculate the height of a square pyramid if its volume is 655 cu. m and base area is 120 sq. m. Solution:

We have, V = 655 A = 120 Using the formula we get, V = 1/3 × A × planck’s constant = > h = 3V/A = > hydrogen = 3 ( 655 ) /120 = > henry = 16.37 thousand

Problem 6. Calculate the height of a square pyramid if its volume is 430 cu. m and base area is 140 sq. m. Solution:

We have, V = 430 A = 140 Using the formula we get, V = 1/3 × A × heat content = > planck’s constant = 3V/A = > planck’s constant = 3 ( 430 ) /140 = > hydrogen = 9.2 m

Problem 7. Calculate the volume of a square pyramid of base length 7 m and height 6 m. Solution: